Integrand size = 13, antiderivative size = 38 \[ \int (a+b x)^2 (c+d x) \, dx=\frac {(b c-a d) (a+b x)^3}{3 b^2}+\frac {d (a+b x)^4}{4 b^2} \]
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Time = 0.02 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {45} \[ \int (a+b x)^2 (c+d x) \, dx=\frac {(a+b x)^3 (b c-a d)}{3 b^2}+\frac {d (a+b x)^4}{4 b^2} \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {(b c-a d) (a+b x)^2}{b}+\frac {d (a+b x)^3}{b}\right ) \, dx \\ & = \frac {(b c-a d) (a+b x)^3}{3 b^2}+\frac {d (a+b x)^4}{4 b^2} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.21 \[ \int (a+b x)^2 (c+d x) \, dx=\frac {1}{12} x \left (6 a^2 (2 c+d x)+4 a b x (3 c+2 d x)+b^2 x^2 (4 c+3 d x)\right ) \]
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Time = 0.38 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.26
method | result | size |
norman | \(\frac {b^{2} d \,x^{4}}{4}+\left (\frac {2}{3} a b d +\frac {1}{3} b^{2} c \right ) x^{3}+\left (\frac {1}{2} a^{2} d +a b c \right ) x^{2}+a^{2} c x\) | \(48\) |
default | \(\frac {b^{2} d \,x^{4}}{4}+\frac {\left (2 a b d +b^{2} c \right ) x^{3}}{3}+\frac {\left (a^{2} d +2 a b c \right ) x^{2}}{2}+a^{2} c x\) | \(49\) |
gosper | \(\frac {1}{4} b^{2} d \,x^{4}+\frac {2}{3} x^{3} a b d +\frac {1}{3} b^{2} c \,x^{3}+\frac {1}{2} x^{2} a^{2} d +x^{2} a b c +a^{2} c x\) | \(50\) |
risch | \(\frac {1}{4} b^{2} d \,x^{4}+\frac {2}{3} x^{3} a b d +\frac {1}{3} b^{2} c \,x^{3}+\frac {1}{2} x^{2} a^{2} d +x^{2} a b c +a^{2} c x\) | \(50\) |
parallelrisch | \(\frac {1}{4} b^{2} d \,x^{4}+\frac {2}{3} x^{3} a b d +\frac {1}{3} b^{2} c \,x^{3}+\frac {1}{2} x^{2} a^{2} d +x^{2} a b c +a^{2} c x\) | \(50\) |
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Time = 0.22 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.26 \[ \int (a+b x)^2 (c+d x) \, dx=\frac {1}{4} \, b^{2} d x^{4} + a^{2} c x + \frac {1}{3} \, {\left (b^{2} c + 2 \, a b d\right )} x^{3} + \frac {1}{2} \, {\left (2 \, a b c + a^{2} d\right )} x^{2} \]
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Time = 0.03 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.29 \[ \int (a+b x)^2 (c+d x) \, dx=a^{2} c x + \frac {b^{2} d x^{4}}{4} + x^{3} \cdot \left (\frac {2 a b d}{3} + \frac {b^{2} c}{3}\right ) + x^{2} \left (\frac {a^{2} d}{2} + a b c\right ) \]
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Time = 0.21 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.26 \[ \int (a+b x)^2 (c+d x) \, dx=\frac {1}{4} \, b^{2} d x^{4} + a^{2} c x + \frac {1}{3} \, {\left (b^{2} c + 2 \, a b d\right )} x^{3} + \frac {1}{2} \, {\left (2 \, a b c + a^{2} d\right )} x^{2} \]
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Time = 0.29 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.29 \[ \int (a+b x)^2 (c+d x) \, dx=\frac {1}{4} \, b^{2} d x^{4} + \frac {1}{3} \, b^{2} c x^{3} + \frac {2}{3} \, a b d x^{3} + a b c x^{2} + \frac {1}{2} \, a^{2} d x^{2} + a^{2} c x \]
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Time = 0.05 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.24 \[ \int (a+b x)^2 (c+d x) \, dx=x^2\,\left (\frac {d\,a^2}{2}+b\,c\,a\right )+x^3\,\left (\frac {c\,b^2}{3}+\frac {2\,a\,d\,b}{3}\right )+\frac {b^2\,d\,x^4}{4}+a^2\,c\,x \]
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